(x+2)(4x-3)=4x^2-6

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Solution for (x+2)(4x-3)=4x^2-6 equation: 



(x+2)(4x-3)=4x^2-6

We move all terms to the left:

(x+2)(4x-3)-(4x^2-6)=0

We get rid of parentheses

-4x^2+(x+2)(4x-3)+6=0

We multiply parentheses ..

-4x^2+(+4x^2-3x+8x-6)+6=0

We get rid of parentheses

-4x^2+4x^2-3x+8x-6+6=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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